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MATH QUETSION
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Popcorn
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MATH QUETSION
by Popcorn Thu Aug 27, 2009 8:19 pm
[(3x^2-27) / 4)] * [8x^2) / (9-3x)] / [(x^2+3x) / 6]
A. -42x
B. -12x
C. 42x
D. 12x
(I know the answer I want see you guys answer it f3)
A. -42x
B. -12x
C. 42x
D. 12x
(I know the answer I want see you guys answer it f3)
Popcorn- Mushmom
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Detailz- Moderator + Game Master
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Re: MATH QUETSION
by izzy Sun Aug 30, 2009 9:54 pm
lol whered u get that question O_O looks like 1 out of a 7th grade math book -.-
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Popcorn- Mushmom
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Re: MATH QUETSION
by Alex Mon Aug 31, 2009 9:08 am
[(3x^2-27) / 4)] * [8x^2) / (9-3x)] / [(x^2+3x) / 6]
so many things wrong with that equation..
anyway
[(3x^2-27)/4] if just that that cant be changed.
* [(8x^2)/(9-3x)]= (3x^2-27)(8x^2) / 4(9-3x)
= 24x^4-216x^2 / 36-12x
= -192x^2 / (12x-36) then /(x^2+3x)/6
= (-192x^4-516x^2)/6 /12x-36
=(-32x^4-258x^2) /12x-36
=(-290x^2)/(12x-36)
thats the final answer.
all of your options are impossible.
so many things wrong with that equation..
anyway
[(3x^2-27)/4] if just that that cant be changed.
* [(8x^2)/(9-3x)]= (3x^2-27)(8x^2) / 4(9-3x)
= 24x^4-216x^2 / 36-12x
= -192x^2 / (12x-36) then /(x^2+3x)/6
= (-192x^4-516x^2)/6 /12x-36
=(-32x^4-258x^2) /12x-36
=(-290x^2)/(12x-36)
thats the final answer.
all of your options are impossible.
Last edited by Alex on Mon Aug 31, 2009 9:20 am; edited 1 time in total
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Re: MATH QUETSION
by Popcorn Mon Aug 31, 2009 5:30 pm
Invert the third fraction then multiply straight across like this
(3x^2-27)(8x^2) 6
-------------------------------------
4(9-3x) (x^2+3x)
but first we can factor and cross cancel
(3(x-3)(x+3)(8x^2) 6
--------------------------------------…
-12(x-3) x (x+3)
after we cross cancel we get
=-12x
B
(3x^2-27)(8x^2) 6
-------------------------------------
4(9-3x) (x^2+3x)
but first we can factor and cross cancel
(3(x-3)(x+3)(8x^2) 6
--------------------------------------…
-12(x-3) x (x+3)
after we cross cancel we get
=-12x
B
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Music- Owner
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