Latest topics
What our server has:
-Auto-Register-Rebirths
-Working KIN's
-Fm Mobs
-Boss spawner
-Awesome Gm's
-Regular Events
-Working Guilds
-All in one shop
-Job advancer
-Trade button = FM
-In progress max stat item system
-Unlimited FJ
-KoC Reskin of skills
-Damage cap removed
-Super Rebirth
-Wish Ticket System
-Max stat trader for tickets
An ever growing list~
MATH QUETSION
+2
Music
Popcorn
6 posters
MATH QUETSION
by Popcorn Thu Aug 27, 2009 8:19 pm
[(3x^2-27) / 4)] * [8x^2) / (9-3x)] / [(x^2+3x) / 6]
A. -42x
B. -12x
C. 42x
D. 12x
(I know the answer I want see you guys answer it f3)
A. -42x
B. -12x
C. 42x
D. 12x
(I know the answer I want see you guys answer it f3)
Popcorn- Mushmom
- Posts : 117
Points : 145
Location : Don't. -
Music- Owner
- Posts : 209
Points : 258
Age : 30
Location : New Zealand -
Popcorn- Mushmom
- Posts : 117
Points : 145
Location : Don't. -
Detailz- Moderator + Game Master
- Posts : 34
Points : 38
Age : 32
Location : Location Location!
Re: MATH QUETSION
by izzy Sun Aug 30, 2009 9:54 pm
lol whered u get that question O_O looks like 1 out of a 7th grade math book -.-
izzy- Moderator
- Posts : 190
Points : 282
Age : 31
Location : Tegucigalpa, Honduras! -
Popcorn- Mushmom
- Posts : 117
Points : 145
Location : Don't. -
Music- Owner
- Posts : 209
Points : 258
Age : 30
Location : New Zealand -
Re: MATH QUETSION
by Alex Mon Aug 31, 2009 9:08 am
[(3x^2-27) / 4)] * [8x^2) / (9-3x)] / [(x^2+3x) / 6]
so many things wrong with that equation..
anyway
[(3x^2-27)/4] if just that that cant be changed.
* [(8x^2)/(9-3x)]= (3x^2-27)(8x^2) / 4(9-3x)
= 24x^4-216x^2 / 36-12x
= -192x^2 / (12x-36) then /(x^2+3x)/6
= (-192x^4-516x^2)/6 /12x-36
=(-32x^4-258x^2) /12x-36
=(-290x^2)/(12x-36)
thats the final answer.
all of your options are impossible.
so many things wrong with that equation..
anyway
[(3x^2-27)/4] if just that that cant be changed.
* [(8x^2)/(9-3x)]= (3x^2-27)(8x^2) / 4(9-3x)
= 24x^4-216x^2 / 36-12x
= -192x^2 / (12x-36) then /(x^2+3x)/6
= (-192x^4-516x^2)/6 /12x-36
=(-32x^4-258x^2) /12x-36
=(-290x^2)/(12x-36)
thats the final answer.
all of your options are impossible.
Last edited by Alex on Mon Aug 31, 2009 9:20 am; edited 1 time in total
Alex- Owner
- Posts : 66
Points : 97
Age : 31
Music- Owner
- Posts : 209
Points : 258
Age : 30
Location : New Zealand -
Re: MATH QUETSION
by Popcorn Mon Aug 31, 2009 5:30 pm
Invert the third fraction then multiply straight across like this
(3x^2-27)(8x^2) 6
-------------------------------------
4(9-3x) (x^2+3x)
but first we can factor and cross cancel
(3(x-3)(x+3)(8x^2) 6
--------------------------------------…
-12(x-3) x (x+3)
after we cross cancel we get
=-12x
B
(3x^2-27)(8x^2) 6
-------------------------------------
4(9-3x) (x^2+3x)
but first we can factor and cross cancel
(3(x-3)(x+3)(8x^2) 6
--------------------------------------…
-12(x-3) x (x+3)
after we cross cancel we get
=-12x
B
Popcorn- Mushmom
- Posts : 117
Points : 145
Location : Don't. -
Music- Owner
- Posts : 209
Points : 258
Age : 30
Location : New Zealand -
Daisyface- Game Master
- Posts : 8
Points : 8
Age : 30
Location : England
Music- Owner
- Posts : 209
Points : 258
Age : 30
Location : New Zealand -
Daisyface- Game Master
- Posts : 8
Points : 8
Age : 30
Location : England
Permissions in this forum:
You cannot reply to topics in this forum
![*Click Here*](https://2img.net/h/oi37.tinypic.com/sotlaa.png"){kind=link}
» sigh.... im bored and i miss u guys
» my application
» random poster bars O_O
» Hey Guys please read IMPORTANT
» Reporting Tom
» First pruning of accounts.
» HELLO STAFF!
» ugh.. i can't join the hamachi network
» izzy's sporting habits
» Introduction chain!
» list plox :D
» Got any Miscalanious Questions About Installation?
» Server's up and harder! >:]